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Year 7–8 Algebra Diagnostic (60-minute): Expressions, Equations & Linear Relationships
Mathematics
Year 7–8 bridge
AC9M7A02, AC9M7A03, AC9M7A04, AC9M8A02 (expressions, equations, linear relations)
Use variables, simplify & expand expressions, solve 1–2-step equations, and describe linear patterns from tables & stories
Bar models & trial tables | Graphing, generalising & explaining structure

Print via your browser’s print dialog (Ctrl/Cmd + P). This worksheet is designed as a calm diagnostic for Years 7–8.

Learning intention & success criteria

Learning intention

Today I am learning to represent unknowns with variables, simplify and expand algebraic expressions, and solve linear equations from worded situations .

Success criteria

I can:

Tutor note: Invite the student to rewrite the learning intention in their own words.
Warm-up / Prior knowledge

Complete the questions below to get your brain ready.

  1. Evaluate 2n + 5 when n = 7.
  2. Simplify: 5x + 3x − 4.
  3. Expand: 3(4y − 2).
  4. Write an expression for: “ten minus four times a number p”.
Vocabulary / Key ideas
Teaching input – What you need to know

We can use algebra to model real-life situations. We choose a variable for the unknown, write an expression or equation, then use inverse operations to solve and check our work.

Steps for solving a simple linear equation:

  1. Represent: Choose a variable for the unknown and write an equation from the story or pattern.
  2. Solve: Use inverse operations to undo the equation step-by-step on both sides.
  3. Check & interpret: Substitute back in, check the equation is true, then explain what the answer means in the story.
Write your own one-sentence story and matching equation below (include a joining fee or starting amount).
Worked example

Example question:

A music app charges a $6 sign-up fee plus $4 per month. Noah paid $38 in total. For how many months did he have the app?

Step-by-step solution:

  1. Let m be the number of months. Total cost: 4m + 6 = 38.
  2. Subtract 6 from both sides: 4m = 32. Divide both sides by 4: m = 8.
  3. Check: 4 × 8 + 6 = 32 + 6 = 38. This matches the total. So Noah had the app for 8 months.

Why this works:

We represent a constant rate ($4 per month) with a coefficient and the sign-up fee as a constant. Using inverse operations keeps both sides of the equation balanced so the solution is still true.

In your own words, explain why we subtract 6 before dividing by 4.
Guided practice (We do)

Use the worked example to help you answer these questions.

  1. A taxi charges a $5 flagfall plus $3 per kilometre. The fare was $26. How many kilometres did the taxi travel? Let k be kilometres.
  2. A sports club charges a $12 joining fee plus $7 per visit. Mia paid $54 in total. How many visits did she make? Let v be visits.
  3. You start with $10 on a travel card and lose $2 for each bus trip. After some trips you have $ 2 left. How many trips did you take? Let t be trips.

Adjustments:

Support: For each question, make a small trial table (input → output) to explore values before writing the equation.

Challenge: For Q1 and Q2, write the rule as an equation and sketch a quick graph showing the intercept and rate of change.

Independent practice (You do)

Now try these on your own. Use the example and your notes to help.

  1. Simplify: 6a + 2a − 9.
  2. Expand: 4(3b − 1).
  3. Solve: 2x + 7 = 19.
  4. Solve: 5y − 3 = 2.
  5. Solve: t/4 + 6 = 11.
  6. Cost story: A game costs $15 plus $4 per sticker pack. You pay $47 in total. How many sticker packs did you buy? Let s be the number of sticker packs.
  7. Table → rule:
    Items (x): 0, 1, 2, 3
    Total (y): −2, 1, 4, 7

    (a) What is the rule for y in terms of x?
    (b) Use your rule to find y when x = 10.
  8. Perimeter story: A rectangle has width 5 cm and length (3m + 2) cm. Its perimeter is 26 cm. Find the value of m.
Extension / Enrichment (Optional)

Create your own linear story involving a starting amount and a “per” amount (for example, streaming, rides, savings, or fundraising).

  1. Write a short story for the situation.
  2. Write an equation using a variable to represent the unknown.
  3. Choose a total and solve your equation.
  4. Explain what the solution means in your story and sketch a quick graph of your rule.
Reflection

Prep–Year 2

Circle how you feel about today’s work:

😊
😐
🙁

Today I learned…

Years 3–12

What did I do well?

What was challenging?

What strategy helped me succeed?

Materials (if needed)

Answer key — For parents & tutors

Warm-up answers

  1. 2n + 5 when n = 7: 2 × 7 + 5 = 14 + 5 = 19.
  2. 5x + 3x − 4 = 8x − 4.
  3. 3(4y − 2) = 12y − 6.
  4. “ten minus four times a number p”: 10 − 4p.

Guided practice answers

  1. Taxi: 5 + 3k = 26 ⇒ 3k = 21 ⇒ k = 7 km.
  2. Sports club: 12 + 7v = 54 ⇒ 7v = 42 ⇒ v = 6 visits.
  3. Travel card: 10 − 2t = 2 ⇒ −2t = −8 ⇒ t = 4 trips.

Independent practice answers

  1. 6a + 2a − 9 = 8a − 9.
  2. 4(3b − 1) = 12b − 4.
  3. 2x + 7 = 19 ⇒ 2x = 12 ⇒ x = 6.
  4. 5y − 3 = 2 ⇒ 5y = 5 ⇒ y = 1.
  5. t/4 + 6 = 11 ⇒ t/4 = 5 ⇒ t = 20.
  6. 15 + 4s = 47 ⇒ 4s = 32 ⇒ s = 8 sticker packs.
  7. Table: difference in y is +3 each time, so y = 3x − 2.
    (a) Rule: y = 3x − 2.
    (b) When x = 10, y = 3 × 10 − 2 = 30 − 2 = 28.
  8. Perimeter P = 2L + 2W.
    L = (3m + 2), W = 5, P = 26.
    2(3m + 2) + 2(5) = 26
    6m + 4 + 10 = 26 ⇒ 6m + 14 = 26 ⇒ 6m = 12 ⇒ m = 2.
    (Length is then 3 × 2 + 2 = 8 cm.)

Extension model response (sample)

Example: “A rideshare app charges a $5 booking fee plus $3 per kilometre.” Rule: C = 3k + 5.
If the total cost is $26, then 3k + 5 = 26 ⇒ 3k = 21 ⇒ k = 7 km.
On a graph, the y-intercept (5) shows the booking fee and the slope (3) shows the cost per kilometre.